Javascript And Automatic Semicolon Insertion
Solution 1:
This code will become:
var z = x;
++ ++ y;
The ++ ++ y
is the root of the problem. Let’s look at why...
++ ++ y
gets evaluated as ++(++y)
. The first step is to evaluate (++y)
. The ++
operator increments the value referenced by the variable it is next to, and returns the incremented value. The important part here is that it does not return a reference, just a value. So the second step would be ++(1)
, (or whatever ++y
yielded), which is an error, since only references can be incremented.
Solution 2:
That evaluates to:
var x = 0, y = 0;
var z = x ++ ++ y; //MAKES NO SENSE!
Solution 3:
The grammar does not allow a new-line to precede a ++
or --
operator; such a new-line must be converted to a ;
. Consequently, the expression must be parsed as though it had been:
var x = 0 , y = 0 ;
var z = x ;
++ ;
++ y ;
The third line is illegal.
References:
Section 7.9.1, "Rules of Automatic Semicolon Insertion", rule 3
Section 11.3, "11.3 Postfix Expressions".
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