Canvas Drawimage With Round Corners
I'm using this coverflow script on my website and I don't know how to output the canvas with rounded corners. This is the code that draws the image ctx.drawImage(image, cropLeft, c
Solution 1:
You can use context.clip()
to draw an image that's clipped inside a rounded rectangle
First draw a rectangle with rounded corners (no need to stroke or fill):
// draw a rounded rectangle
ctx.beginPath();
ctx.moveTo(x + radius, y);
ctx.lineTo(x + width - radius, y);
ctx.quadraticCurveTo(x + width, y, x + width, y + radius);
ctx.lineTo(x + width, y + height - radius);
ctx.quadraticCurveTo(x + width, y + height, x + width - radius, y + height);
ctx.lineTo(x + radius, y + height);
ctx.quadraticCurveTo(x, y + height, x, y + height - radius);
ctx.lineTo(x, y + radius);
ctx.quadraticCurveTo(x, y, x + radius, y);
ctx.closePath();
Then call context.clip which will cause all future drawings to be clipped inside the rect
ctx.clip();
Finally, draw your image inside that rectangle and your image will be clipped round.
ctx.drawImage(img,10,10,102,77);
Here is example code and a Fiddle: http://jsfiddle.net/m1erickson/FLaee/
<!doctype html>
<html>
<head>
<link type="text/css" media="all" href="css/reset.css" /> <!-- reset css -->
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<style>
body{ background-color: ivory; }
#canvas{border:1px solid red;}
</style>
<script>
$(function(){
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var img=new Image();
img.onload=function(){
ctx.save();
roundedImage(10,10,102,77,10);
ctx.clip();
ctx.drawImage(img,10,10,102,77);
ctx.restore();
}
img.src="https://dl.dropboxusercontent.com/u/139992952/stackoverflow/sky-bg2.jpg";
function roundedImage(x,y,width,height,radius){
ctx.beginPath();
ctx.moveTo(x + radius, y);
ctx.lineTo(x + width - radius, y);
ctx.quadraticCurveTo(x + width, y, x + width, y + radius);
ctx.lineTo(x + width, y + height - radius);
ctx.quadraticCurveTo(x + width, y + height, x + width - radius, y + height);
ctx.lineTo(x + radius, y + height);
ctx.quadraticCurveTo(x, y + height, x, y + height - radius);
ctx.lineTo(x, y + radius);
ctx.quadraticCurveTo(x, y, x + radius, y);
ctx.closePath();
}
}); // end $(function(){});
</script>
</head>
<body>
<canvas id="canvas" width=300 height=300></canvas>
</body>
</html>
Solution 2:
The problem with the clip() solution is that Chrome will render it with the borders non antialiased, as demonstrated in this question.
One solution would be to do it with globalCompositeOperation as Daniel says in his answer:
//set-up - probably only needs to be done once
var scratchCanvas = document.createElement('canvas');
scratchCanvas.width = 100;
scratchCanvas.height = 100;
var scratchCtx = scratchCanvas.getContext('2d');
//drawing code
scratchCtx.clearRect(0, 0, scratchCanvas.width, scratchCanvas.height);
scratchCtx.globalCompositeOperation = 'source-over'; //default
//Do whatever drawing you want. In your case, draw your image.
scratchCtx.drawImage(imageToCrop, ...);
//As long as we can represent our clipping region as a single path,
//we can perform our clipping by using a non-default composite operation.
//You can think of destination-in as "write alpha". It will not touch
//the color channel of the canvas, but will replace the alpha channel.
//(Actually, it will multiply the already drawn alpha with the alpha
//currently being drawn - meaning that things look good where two anti-
//aliased pixels overlap.)
//
//If you can't represent the clipping region as a single path, you can
//always draw your clip shape into yet another scratch canvas.
scratchCtx.fillStyle = '#fff'; //color doesn't matter, but we want full opacity
scratchCtx.globalCompositeOperation = 'destination-in';
scratchCtx.beginPath();
scratchCtx.arc(50, 50, 50, 0, 2 * Math.PI, true);
scratchCtx.closePath();
scratchCtx.fill();
//Now that we have a nice, cropped image, we can draw it in our
//actual canvas. We can even draw it over top existing pixels, and
//everything will look great!
ctx.drawImage(scratchCanves, ...);
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