Javascript/ajax To Php Page With Either Post Or Get
Solution 1:
The correct way to send data via POST with jQuery is with the data
property.
An example is:
functionupdateDB(page1,page2)
{
$.ajax({
type: 'POST',
url: 'update.php',
data: {
page1: page1,
page2: page2
},
success: function() {
window.location = "http://google.com";
},
cache: false
});
}
I have also added alert
on success, as well as disabling cache. Even though this is post, IE will cache post requests to pages that have been requested with get.
I would highly recommend using MySQLi, or at the very least escaping the query:
include"connect.php";
$page1 = mysql_real_escape_string($_POST['page1']);
$page2 = mysql_real_escape_string($_POST['page2']);
mysql_query("UPDATE `pages` SET `page1` = '$page1'") ordie(mysql_error());
If you want to change the page afterwards from the href simply do this:
<script>functionlinkme(_this) {
window.event.preventDefault();
//do all the code with ajaxwindow.location = _this.href;
}
</script><ahref="http://google.com"onclick="linkme(this)">Clicky</a>
Solution 2:
You have forgot '' at your strings(update.php and page1/2), which your browser console should wine about: "Uncaught ReferenceError: update is not defined". See more about debugging here: https://developers.google.com/chrome-developer-tools/docs/javascript-debugging
Also you need to put your data in an data object.
$.ajax({
type: 'POST',
url: 'update.php',
data: {
page1: page1,
page2: page2
}
}).done(function(data){
alert('got:' + data);
});
Se more at jquery documentation: http://api.jquery.com/jQuery.ajax/
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